free body diagram
  • (9_61) team 5

New_Bitmap_Image_kjj.PNG
New_Bitmap_Image_kjj.PNG


SMB =0
R
A*(5.4) – (6.2 * 1.8) – (3 * 3.6 * 1.8) = 0
R
A = 5.667 kN
SFY=0
R
B +RA= 6.2 + (3 * 3.6) = 17 kN
R
B = 17 – 5.667 = 11.333 kN
R
A = 5.667 kN ; RB = 11.333 kN
external image 594955273.jpg
external image 594955273.jpg

external image 427614568.png
external image 427614568.png


At max deflection → dv/dx =0
max deflection will be at 1.8<x<3.6

so max deflection will occur at X= 2.855 and max deflection will be 1.648 mm