The following was originally published June 4, 2011 at http://aero103.blogspot.com/2011/06/853-team-5.html
(8-17)
Determine the smallest allowable diameter of the solid shaft ABCD knowing that τall=60 MPa and that the radius of disk B is r= 80 mm
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M=0
T-Pr=0
P=7.5*103 N
RA=Rc=12P=3.75*103 N
MB=3.75*103150*10-3=562.5 N.M
Critical section at point B
JC=π2C3=2πM2+T2τall=2π562.52+600260*106=8.726*10-6 m3
C=20.58*10-3m D=2C=41.2*10-3m
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